
Steve S. answered 04/01/14
Tutor
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(3)
Tutoring in Precalculus, Trig, and Differential Calculus
Use a half-angle formula to find the exact value of tan(3pi/8).
tan(3pi/8) = tan((3pi/4)/2)
sin(3pi/4) = sin(pi/4) = 1/√(2)
cos(3pi/4) = –cos(pi/4) = –1/√(2)
tan(t/2) = (1–cos(t))/sin(t)
tan(3pi/8) = (1–cos(3pi/4))/sin(3pi/4)
tan(3pi/8) = (1–(–1/√(2)))/(1/√(2))
= (1+1/√(2))/(1/√(2)) = √(2) + 1
tan(3pi/8) = tan((3pi/4)/2)
sin(3pi/4) = sin(pi/4) = 1/√(2)
cos(3pi/4) = –cos(pi/4) = –1/√(2)
tan(t/2) = (1–cos(t))/sin(t)
tan(3pi/8) = (1–cos(3pi/4))/sin(3pi/4)
tan(3pi/8) = (1–(–1/√(2)))/(1/√(2))
= (1+1/√(2))/(1/√(2)) = √(2) + 1
Mohit K.
Thanks it is very helpful
10/11/17