What is the molarity?

Question

what is the molarity of a solution of sucrose, C12H22O11, that contains 89.0 g of sucrose in 0.50 L of solution.

Answer 1

molarity = (moles of solute) / (volume of solution in liters)

 

moles = (weight in grams) / (molecular weight) = (89.0 g) / (342.30 g/mol) = 0.260 mols

 

molarity = (0.260 mols ) / (0.50 L) = 0.520 mols/L

Answer 2

• Molarity is equal to the mols divided by the volume of solution. (M=mols/Liters) 
• Calculate the mols of sucrose.
• mols of sucrose is equal to 89.0 g of sucrose x       1 mol of sucrose           = mols of sucrose

                                                                                     molecular weight of sucrose 

• divide the mols of sucrose calculated by volume (0.50L) to determine the molarity of the solution.