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Using the quadratic formula to solve 5x = 6x2 – 3, what are the values of x?

Using the quadratic formula to solve 5x = 6x2 – 3, what are the values of x?

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Steve S. | Tutoring in Precalculus, Trig, and Differential CalculusTutoring in Precalculus, Trig, and Diffe...
5.0 5.0 (3 lesson ratings) (3)
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Using the quadratic formula to solve 5x = 6x^2 – 3, what are the values of x?

5x = 6x^2 – 3

Subtract 5x from both sides:

0 = 6x^2 – 5x – 3

a = 6, b = -5, c = -3

x = (-b ± √(b^2 - 4ac))/(2a)

x = (-(-5) ± √((-5)^2 - 4(6)(-3)))/(2(6))

x = (5 ± √(25 + 72))/12

x = (5 ± √(97))/12

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Thanks for the help, Steve.
Stephen W. | Othello, Eltopia, Connell, Pasco, West Pasco - I am in your area!Othello, Eltopia, Connell, Pasco, West P...
4.9 4.9 (43 lesson ratings) (43)
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5x = 6x^2 - 3

First you need to put the equation into ax^2 + bx + c = 0. For this problem, all we have to do is subtract 5x from both sides:
0 = 6x^2 - 5x - 3

'a' is 6, 'b' is -5, and 'c' is -3

Now you plug them into the quadratic formula and carefully work down the answer.
 
"Negative 'b' plus or minus the square root of 'b' squared minus four 'a''c', all over 2'a'"
 
Hope this helps. If you need a visual quadratic formula to use, please look it up online. I don't have a way to attach the image I normally use as a tutoring aid.
 
If you have any questions, please feel free to contact me.
 
 
 
 
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