**A cylindrical can is to have a volume of 1L.**

**a) Find the height and radius of the can that will minimize the surface area**^{3}

^{2}y = 1000 cm

^{3}. So y = 1000/(pi)x

^{2}

^{2}+ 2(pi)xy

^{2}for y, the surface area is:

^{2}+ 2(pi)x*1000/(pi)x

^{2}= 2(pi)x

^{2}+ 2000x

^{-1}

^{-2}

^{-2}

^{-2}= 4(pi)x

^{3}

^{1/3}= 10(1/2(pi))

^{1/3}≈ 5.42 cm

^{2}= 10.84 cm

^{2}(10.84) = 1000

**b) What is the ratio of the height to the diameter?****You're on your own for this question! ;-)**

*Do pop cans have a similar ratio? If not, why?*
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