Hailey H.
asked 05/12/17simplify the difference quotients
f(x+h)-f(x)/h and f(x)-f(a)/x-a for the following function by rationalizing the numerator.
f(x)=sqr rt of x^2-8
More
1 Expert Answer
Inactive Tutor answered 05/12/17
Tutor
New to Wyzant
f(x + h) - f(x)
____________ =
h
√((x + h)2 - 8) - √(x2 - 8)
_______________________ =
h
√(x2 + 2xh + h2 - 8) - √(x2 - 8)
___________________________ =
h
Multiply the expression by √(x2 + 2xh + h2 - 8) + √(x2 - 8)
______________________________
√(x2 + 2xh + h2 - 8) + √(x2 - 8)
√(x2 + 2xh + h2 - 8) + √(x2 - 8)
x2 + 2xh + h2 - 8 - (x2 - 8)
________________________________
h[√(x2 + 2xh + h2 - 8) + √(x2 - 8)]
x2 and the constant term 8 on top cancel each other out.
h(2x + h)
__________________________________
h[√(x2 + 2xh + h2 - 8) + √(x2 - 8)]
h cancels on top and bottom. Final answer is
2x + h
_______________________________
√(x2 + 2xh + h2 - 8) + √(x2 - 8)
Inactive Tutor
If you set h=0 and simplify even further, you get an expression that is the derivative of f(x). You would end up with
2x / 2√(x2 - 8) =
x / √(x2 - 8) ----> derivative of √(x2 - 8)
Report
05/12/17
Hailey H.
what about for the second quotient, f(x)-f(a)/x-a
Report
05/12/17
Inactive Tutor
Overall, the formula I used here is the same as the formula you provided here.
f(x + h) - f(x) f(x) - f(a)
____________ = ___________
h x - a
= f(x + h) - f(x)
___________
(x + h) - x
= f(x + h) - f(x)
____________
h
Report
05/12/17
Inactive Tutor
f(x) - f(a)
________ =
x - a
√(x2 - 8) - √(a2 - 8)
_________________ =
x - a
x2 - 8 - (a2 - 8)
__________________________ =
(x - a)[√(x2 - 8) + √(a2 - 8)]
(x - a)(x + a)
__________________________ =
(x - a)[√(x2 - 8) + √(a2 - 8)]
x + a
_____________________ =
√(x2 - 8) + √(a2 - 8)
Report
05/13/17
Still looking for help? Get the right answer, fast.
Ask a question for free
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Find an Online Tutor Now
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Michael A.
05/12/17