[0,2π ]: sin²x+sinx=0

Question

possible answers: a. 0,π,3π/2   b. 0,π,π/3,2π/3   c. 0,π,4π/3,5π/3   d. 0,π,π/3,5π/3

Answer 1

Factor your equation: sin x(sin x + 1) = 0.

 

Set each factor (separately) to zero, i.e., use the Zero Product Property.   

 

Easy, once you're on that path.