
Arturo O. answered 05/09/17
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The problem statement incorrectly calls v the distance (as Walter pointed out). It should call v the final speed attained at the bottom of the fall, and s is the distance fallen. The correct formula to use is the kinematic relationship
v2 = 2gs
where
v = speed at bottom in ft/sec
g = acceleration of gravity = 32 ft/sec2, which makes 2g = 64 ft/sec2
s = distance fallen = 20 feet
Then
v = √(2gs) = √(64 x 20) ft/sec ≅ 35.78 ft/sec