(1- lxl )/(2 - lxl) ≥ 0
There are 2 cases to consider:
Case 1: numerator ≥ 0 and denominator > 0
lxl ≤ 1 and lxl < 2 So, -1≤x≤1 and -2<x<2.
For the inequalities to be true, we must have -1≤x≤1.
Case 2: numerator < 0 and denominator < 0
lxl>1 and lxl>2 So, x>1 or x<-1, and x>2 or x<-2,
So, x>2 or x<-2.
Solution set: (-∞,-2) ∪ [-1,1] ∪ (2,∞)