
Herb K. answered 05/06/17
Tutor
4.5
(34)
Semi-Retired College Professor - MIT Grad - very patient, experienced
f(x) = x^2 + x - 1; g(x) = x - 1;
f(g(x)) - g(f(x) = f(g) - g(f) = (g^2 + g - 1) - (f - 1)
= [(x - 1)^2 + (x - 1) - 1] - [(x^2 +x - 1) - 1]
= [(x^2 - 2x + 1) + x - 2] - [x^2 + x - 2]
= [x^2 - x - 1] - [x^2 + x - 2]
= -2x + 1
Amy K.
05/06/17