How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated?

Question

Help....... this is so hard

Answer 1

Well, it's hard because you forgot the rules for DIVISIBILITY.

The last digit MUST be a five !!!!!!!!!!

 

   Then pick 2 from the remaining five digits without replacement.

   There are 5 choices for the first digit.

   There are 4 choices for the second digit.

 

  20 possibilities. 

 

     235     325   625     725     925

     265     365   635     735     935

     275     375   675     765     965

     295     395   695     795     975