If an electron has orbital angular momentum quantum number l=7, then it will have an orrbital angular momentum equal to

Question

a.7(h/2π)  b.42(h/2π) c.√7(h/2π) d.√(h/2π)

 

Answer 1

Recall from basic quantum physics that

L² = l(l + 1) [h/(2π)]² ⇒ L = √[l(l +1)] h/(2π)

 

The answer should be

 

L  = √[7(7 +1)] h/(2π) = √56 h/(2π) = 2√14  h/(2π)

 

However, that answer is not among the choices.  Pleased double-check the problem statement.