Is the sequence sin n bounded?

Question

How do I figure out if its bounded or not ?

Answer 1

Of course, argument n must mean radian measure. since the sequence is a succession of different sine values (for peculiar real arguments--peculiar in not being nicely behaved submultiples of pi radians), we nevertheless know that each element of the sequence is ≤1 and≥-1, i.e. upper bound 1, lower bound -1.

 

In a word, YES