
Gene G. answered 04/22/17
Tutor
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(257)
Retired Electrical Engineer Helping People Understand Algebra
The way to type these in line is to use parentheses:
6/(y+1) + y/(y-2) = 6/(y+1) • y/(y-2)
The common denominator for the addition is:
(y-1)(y+2)
6(y-2)/(y-2)(y+1) + y(y+1)/(y-2)(y+1) = 6y/(y-2)(y+1)
These denominators are all the same.
Multiply both sides by (y-2)(y+1).
6(y-2) + y(y+1) = 6y
6y-12 + y2+y = 6y
y2+y-12=0
(y-3)(y+4) = 0
y = 3, -4