Find the length of the segment with endpoints of (3,2) and (-3,-6).

Question

please explain how to solve this problem. thank you.

Answer 1

Use the distance formula:

 

d = √((x₂-x₁)²+(y₂-y₁)²)

 

where (x₁,y₁)=(3,2) and (x₂,y₂)=(-3,-6).  Plug in the values and compute the answer.

Answer 2

Length of the segment = √((y₂ - y₁)² + (x₂ - x₁)²)

Plug the values y₁ = 2, y₂ = -6, x₁ = 3, x₂ = -3

 

Length of segment = √((-6-2)² + (-3-3)²) = √(64+81) = √145 = 12.04