
Parviz F. answered 02/21/14
Tutor
4.8
(4)
Mathematics professor at Community Colleges
a) 1/9 ei(0)
r = 1/9
Θ = 0°
b)
6 + 6i
r = √( 6^2 + 6 ^2) = √72 = 6 √2
θ = tan-1 ( 6/6=1) = ∏/4
6√2 ei∏/4
d) - 3 - 3i
r = √( 3^2 + 3^2) = 3√2
θ = tan-1( -3/ -3) = 5π/4
3√2 ei5∏/4