 
Andrew M. answered  04/16/17
Tutor
                    
    New to Wyzant
            Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
I assume you are supposed to solve the system of equations....
−2x+5y=13   {equation 1}
16x+3y=25 {equation 2}
16x+3y=25 {equation 2}
We can easily use elimination.  Multiply equation 1
by 8 and add the equations to eliminate the x variable.
-16x + 40y = 104
 16x +  3y  =   25
------------------------
           43y = 129
             y = 129/43
             y = 3
Substitute 3 in for y in one of the original
equations to solve for x
-2x + 5(3) = 13
-2x + 15 = 13
-2x = -2
x = 1
Your point of intersection, the solution, is (1,3) 
 
     
             
                     
                    