Systems?

Here is another way to solve this problem.

To solve it, what you want to do is isolate one of the x's or y's, plug what you get into one equation, solve for one variable, and then other (phew... that was a lot to write... let me just show you).

Our equations are: 4x + 5y = 12 and 3x + 4y = 10

WE GOT THIS!

1. **Solve for a variable.** We will use the 2nd equation and solve for "x."

3x + 4y = 10 ----> 3x = 10 - 4y ----> **x = (10/3) - (4y/3).**

2. Look! Now we know what x is! Let's plug this into the first equation!!!

4x + 5y = 12 ----> 4(10/3) - (4y/3) = 12 ----> (40/3) - (4y/3) = 12

3. **Isolate and solve for the "y" variable**.

(-4y/3) = 12 - (40/3) ----> **y = 4**

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**4. LOOK! We know what "y" is.

**Plug this in to either equation to get "x!"**

** 4x + 5y = 12 ----> 4(x) + 5(4) = 12 ----> 4x = -8 ----> x = -2**