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how to solve each system by elimination -6x-6y=6 and -6x+3y=-12

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2 Answers

 -6X - 6Y = 6
 -6X  +3Y = -12
 
  Simplify both equations:
 
        X + Y = -1
       2X - Y = 4
        3X = 3
            X =1
 
          Y =-2
 
      
  
Hi Angelica;
-6x-6y=6
-6x+3y=-12
Let's subtract the second equation from the first...
-6x-(6x)=6x+6x=0
-6y-3y=-9y
6--12=6+12=18
0-9y=18
The x is eliminated...
-9y=18
Let's divide both sides by -9...
(-9y)/-9=18/-9
y=-2
Let's plug this into either equation to establish the value of x.
I randomly select the first equation...
-6x-6y=6
-6x-[(6)(-2)]=6
-6x-(-12)=6
Subtracting a negative number is identical to adding a positive number...
-6x+12=6
Let's subtract 12 from both sides...
-6x+12-12=6-12
-6x=-6
Let's divide both numbers by -6...
(-6x)/-6=-6/-6
x=1
Let plug both values into the second equation to verify...
-6x+3y=-12
[(-6)(1)]+[(3)(-2)]=-12
-6+-6=-12
-12=-12