Hi Angelica;
6x6y=6
6x+3y=12
Let's subtract the second equation from the first...
6x(6x)=6x+6x=0
6y3y=9y
612=6+12=18
09y=18
The x is eliminated...
9y=18
Let's divide both sides by 9...
(9y)/9=18/9
y=2
Let's plug this into either equation to establish the value of x.
I randomly select the first equation...
6x6y=6
6x[(6)(2)]=6
6x(12)=6
Subtracting a negative number is identical to adding a positive number...
6x+12=6
Let's subtract 12 from both sides...
6x+1212=612
6x=6
Let's divide both numbers by 6...
(6x)/6=6/6
x=1
Let plug both values into the second equation to verify...
6x+3y=12
[(6)(1)]+[(3)(2)]=12
6+6=12
12=12
2/3/2014

Vivian L.