how to solve this

Question

An aluminum wire having a cross-sectional area of 4.00 ✕ 10-6 m2 carries a current of 6.00 A. Find the drift speed of the electrons in the wire. The density of aluminum is 2.70 g/cm3. Assume each aluminum atom supplies one conduction electron.

Answer 1

I = nevA

v= I/(neA)

 

ρ,density = 2700 kg/m³

n = # of electrons/V = # of atoms/V = N_a * # moles/V= N_a * m/Mw  =N_a * ρ * V /Mw/V = N_a*ρ/Mw

 Plug into equation:

 

v = I/(N_a*ρ/Mw)/e/A =I*Mw/(N_a*ρ*e*A)

where

N_a, avrogado's # = 6.022×10²³ atoms/mole

Mw, molecular weight of Aluminum = 27 g/mole

e, charge of one electron = 1.6 × 10^-19C

A = 4×10^-6 m²

I = 6 Amps

 

I hope this helps you understand the question and how to approach it Porcia.