
Kenneth S. answered 04/15/17
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
One way to have the described event occur is to pick two £1 coins and one 50 p coin.
If only one coin valued at £1 were picked, the remaining £1.5 worth cannot be obtained by picking two 50p coins.
So it looks as if the only scenario satisfying the event described is as described in the first sentence above.
3C2 is # of ways of picking the two big value coins, and 7C1 is the # of ways of picking the coin of lesser value.
Therefore P(£2.50) = 3•7/10C3 ...I leave it to lyou to finish this calculation