Clay S.

asked • 11/05/14

Probability question dealing with an or statement.

A bag contains 9 Buttercups & 3 Kisses. A box contains 4 Jolly Ranchers, 6 Life Savers, and 10 Werthers. If we randomly select 1 item out of the bag & 1 item from the box what is the probability one will select: 

a) a Buttercup or Werther?
 
Our question is can you solve this problem by doing it this way because or means we need to add the probabilities together.  Problem is the result is greater than 1 and in probability 1 means it certain to happen so no result should be greater than 1.
 
9/12 + 10/20 = 180/240 + 120/240 = 300/240 = 5/4
 
or
 
would it have to be solved this way since you are only looking at picking one item out of the total amount of candies in the end which is either 1 buttercup or 1 werthers. 
 
9/32 + 10/32 = 19/32

1 Expert Answer

By:

Clay S.

The problem I am having trying to understand that answer is that it's 5/4  which is greater than 1.  In probability 1 means that an event is certain to happen.  How can the answer be 5/4 which is more than one which means that it is more than certain to happen.  If it's certain to happen than it will happen you can't have anything that would be more than certain to happen because it's already going to happen.
 
thoughts?
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11/05/14

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