Find all solutions in the interval [0, 360]

Question

Find all solutions in the interval [0, 360°]. Sin(4t)=(√3)/2

Answer 1

Note: √3 / 2 = sin 60° = sin 120°

sin 4t = √3 / 2

 

4t = 360k + 60 or 4t = 360k + 120

 

t = 90k + 15 or 90k + 30

 

In the [0°,360°], you get:

 

15° , 30° , 105° , 120° , 195° , 210° , 285° , 300°