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How much fuel was used?

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1 Answer

x = kiloliters of fuel used in 13.5 hours
 
y = kiloliters of fuel that would be used in another 0.75 hours
 
x + y = 180
 
x/13.5 = y/0.75 ==> y = 0.75x/13.5
 
x + 0.75x/13.5 = 180
 
x(1 + 3/54) = 180
 
x(19/18) = 180
 
x = 180*18/19