How much heat is required to change the temp of a 20 kg iron bar from 150-350 degrees?

Question

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Answer 1

Q = amount of heat required

m = mass of iron = 20 kg

ΔT = temperature change = (350-150)°C = 200°C (I assume you are working in ºC.  You should state that in the problem.)

c = specific heat of iron = 0.444 kJ/(kg°C)  [Look this up in your book to verify.]

 

Q = mcΔT = (20 kg) [0.444 kJ/(kg°C)] (200°C) = 1776 kJ