Equation for axis of symmetry

Question

I need help with the quadratic formula

Answer 1

For ax² + bx + c = 0

 

The x coordinate of the vertex is 

at x = -b/2a

 

The axis of symmetry is the line

x = -b/2a

 

Example:

2x² - 6x + 7 = 0

This is a parabola opening

upward from the vertex.

The axis of symmetry is

x = -b/2a

a=2, b = -6, c = 7

 

x = -(-6)/[2(2)]

x = 6/4

x = 3/2 is the axis of symmetry..

The vertical line through the vertex.