
Stephanie P. answered 04/01/17
Tutor
5
(1)
Pre-Occupational Therapy Undergraduate Student
Hi! I'm Stephanie.
This problem looks a little scary, but it's not bad if you break it down. It needs to be solved using a system of two equations. Lets start with the first part of this question. "John's weight is 3/5 of Peter's weight." Lets use J for John an P for Peter. So, John is 3/5 of Peter;
J=3/5P
Now, for the second part: "If John were to jain 8 pounds, he'd weigh 2/3 of Peter's weight." So;
J+8=2/3P
Now, what we're trying to figure out is Peter's weight.
We already know that J=3/5P from the first equation. What we're going to do is use what's called the substitution method. Look at this:
3/5P+8=2/3P
Here, we have replaced the J in the second equation, with 3/5P, because as we know, they are equivalent. So now all we have left is simply solving the equation.
3/5P +8 = 2/3P → 2/3-3/5=1/15
-3/5P -3/5P
8 = 1/15P
1/15 1/15
120=P
Now, we know that Peter weighs 120 pounds. Now, lets check our answer using the original two equations.
J=3/5(120)
J=72
J=2/3(120)-8
J=80-8
J=72
So, now that we know that the equations work, we know the final answer to the problem:
Peter weights 120 pounds.