Dr Gulshan S. answered 04/14/17
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Hello Bertina
When a small stone is dropped in a viscous liquid
(1)The wt mg acts down wards
( 2) an upthrust = (Volume of stone * density of liquid * g )acts upwards ( = Vdg)
(3) A viscous force also acts upwards which increases as the downward speed of stone increases
As a result of these three forces the stone first accelerates downwards for some distance and then acquires a constant velocity called terminal velocity
At this stage the net force on the stone is zero , as the three forces creat zero net force on the stone