
Arturo O. answered 03/22/17
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Are you familiar with L'Hopital's rule for indeterminate forms? I suggest using that rule.
limitx→1 (1 + x - 2√x) / (1 - x) = limitx→1 [1 - 2(1/2)x-1/2] / (-1)
= limitx→1 [-(1 - 1 / √x)] = -(1 - 1) = 0

Arturo O.
You are welcome. Basically, the rule says that when you have a form that approaches 0/0 as in this problem, or ∞/∞, you take the derivative of the numerator and denominator, and try evaluating the ratio of the derivatives at the limit. It will be the same as the ratio of the original numerator and denominator. Note that I took the derivatives and evaluated at 1.
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03/22/17
John B.
03/22/17