
Steve S. answered 03/13/14
Tutor
5
(3)
Tutoring in Precalculus, Trig, and Differential Calculus
2x - y = 3
x + 2y = -6
R1 2, -1, 3
R2 1, 2, -6
R1 > R1 - 2*R2
R1 0, -5, 15
R2 1, 2, -6
R1 > R1 / (-5)
R1 0, 1, -3
R2 1, 2, -6
R2 > R2 - 2*R1
R1 0, 1, -3
R2 1, 0, 0
0x + y = -3
x + 0y = 0
y = -3
x = 0
check:
2(0) - (-3) = 3 √
(0) + 2(-3) = -6 √
[Why keep writing the variables when all the information is in the coefficients and constants?]
x + 2y = -6
R1 2, -1, 3
R2 1, 2, -6
R1 > R1 - 2*R2
R1 0, -5, 15
R2 1, 2, -6
R1 > R1 / (-5)
R1 0, 1, -3
R2 1, 2, -6
R2 > R2 - 2*R1
R1 0, 1, -3
R2 1, 0, 0
0x + y = -3
x + 0y = 0
y = -3
x = 0
check:
2(0) - (-3) = 3 √
(0) + 2(-3) = -6 √
[Why keep writing the variables when all the information is in the coefficients and constants?]