solve the system of equations Thank you
2x-y=3
x+2y=-6
multiply the second equation by -2
-2x-4y=12
add the first equation and the new second equation
2x-y=3
-2x-4y=12
-5y=15
y=-3
substitute into the first equation
2x-(-3)=3
2x+3=3
2x=0
x=0
solution:(0,-3)
using substitution...
2x-y=3
x+2y=-6
x=-2y-6
substitute into the first equation
2(-2y-6)-y=3
-4y-12-y=3
-5y-12=3
-5y=15
y=-3 again,
substitute into the first equation
2x-(-3)=3
2x+3=3
2x=0
x=0 again
these are just two ways to solve the problem; you can solve it in other ways:you can multiply the first equation by 2 and take it from there or solve for y in the first equation and then substitute into the second equation
