log9.2(11.3)t = 2t+1
t(log9.211.3) = 2t+1 Note: log9.211.3 = log11.3/log9.2 ≈ 1.0926455
1.0926455t = 2t+1
-0.9073545t = 1
t ≈ -1.102

Ethan P.
asked 03/20/17Kemal G. answered 03/20/17
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Kemal G.
03/20/17