Dr Gulshan S. answered 03/20/17
Tutor
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(52)
Physics Teaching is my EXPERTISE with assured improvement
Hi Mavis
For r= 0.005 m the entire current is threading through the loop
so
B2 = μ0 I /( 2pi R)
4 pi * 10 -7 / 2pi R = 2* 10-7/ R where R = 0.005 m
B2 = 2* 10-7/ 0.005
= 4*10-5 Tesla
For B1 at a distance r1 = .002 m , we have to take only that fraction of current which threads through area pi r12
Where r1 = 0.002 m