64x^2+8+0 <--------

Question

I need help  understanding real and complex roots

Answer 1

64X² + 8 =0

 

8 (8 X^2 + 1 ) = 0

 

   8X^2 + 1 =0

 

    8 X^2 = -1

 

      X^2 = -1/8

 

       X = ± (1/ 2√2) i = ±((√2) /2) i

 

   Complex numbers unit is i ,   i² = -1