If laser beam hits the bullet proof Lexan glass of a bank with an angle of 45 degrees

Question

If laser beam hits the bullet proof Lexan glass of a bank with an angle of 45 degrees. If the index of refraction for Lexan is 1.585 and the index of refraction for air is 1.000293, What is the angle of the light passing through the Lexan?

Answer 1

This is an application of Snell's Law:

 

n*sinθ = n'*sinθ'

 

where:

 

n = the index of refraction of the initial medium (air in this case)

n' = the index of refraction of the final medium (Lexan glass)

θ = the angle of the incident light beam (45^o)

θ' = the angle of the transmitted light beam (in the glass)

 

You know n, n', and θ.  Solve for θ'

 

Note that the angle is measured from the line normal to the surface.