Steve S. answered • 03/07/14

Tutoring in Precalculus, Trig, and Differential Calculus

Rodela R.

asked • 03/06/14
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Steve S. answered • 03/07/14

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5
(3)
Tutoring in Precalculus, Trig, and Differential Calculus

A floor 5 m by 20 m is covered by square tiles of side 20 cm.

How many tiles are needed?

5 m = 500 cm; so 500/20 = 25 tiles will fit along that side.

20 m = 2000 cm; so 2000/20 = 100 tiles will fit along that side.

So the floor is 25 tiles x 100 tiles = 2500 tiles.

[But what about the grout lines?]

Ebenezer O. answered • 03/06/14

Tutor

4.6
(13)
Aerospace Engr & Air Traffic Control Grad For General Ed. Tutoring

Given

The floor 5m by 20m (total surface area is 100m) and the tiles are 20cm;

1cm = 0.01m

so

20cm = 0.2m

The area of each tile would be 0.2m * 0.2m = 0.04m

To find the total number of tiles needed, we'll divide the size of the total surface area(100m) by the area of each tile(0.04m)

100m / 0.04m = 2500.

So 2500 tiles are needed.

Rodela R.

i dont have the solution but i have the answers in the back of my book and it say's the answer will be 2500 tiles...can u plss recheck

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03/07/14

Ebenezer O.

Thanks for pointing that out....I missed a step but I've corrected it.

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03/07/14

Indira S.

But still the answer is 6 tiles
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07/15/19

Parviz F. answered • 03/06/14

Tutor

4.8
(4)
Mathematics professor at Community Colleges

A = 20m * 5 m = 100 m^{2} = 10 ^6 Cm^{2}

n = 10^6 cm^{2} / ( 20 * 20 cm^{2}) = 2500

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Rodela R.

03/07/14