A 25 ounce solution is 20% alcohol. If 50 ounces of water are added to it, what percent of the new solution is alcohol

Question

I'm not sure on how to go on about this, even though I was given the possible answers I'm just so confused right now

Answer 1

Think about it this way.

First, how many ounces of alcohol is that 20%?
20% is also 1/5. So, we are finding 1/5 of 25. 

5 ounces is the amount of ounces of alcohol in the solution. 

So the question can be rephrased as: A 25 ounce solution has 5 ounces of alcohol and 20 of water. If we add 50 ounces of water, what will be the percent of alcohol in the new solution?

To find the percent, we divide the number of ounces of alcohol by the number of ounces all together, and then multiply that by 100. 

25 + 50 = 75. 
Now we have 75 ounces of the solution, in total. 
We didn't add any alcohol, so of that solution, only 5 ounces is alcohol, still.

Therefore, 5/75 = the proportion of alcohol to the rest of the solution. That is equal to 0.0666666667. 
To get the percent, we multiply by 100. 
The new percentage of alcohol is 0.066666667 times 100. 
You got it from there :)