Meena S. answered 03/04/14
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Hi Daisy,
g(x)=x^3-125/x^2+1
=(x-5)(x^2+5x+25)
now we can find complex roots for (x^2+5x+25),
x^2+5x+25=0
using formula,if ax^2+bx+c=0,
then x= -b ±√b²-4ac ⁄ 2a
substituting a= 1, b= 5, c= 25, we get,
x= -5±√5²-4(1)(25)/ 2(1)
=-5 ±√25-100/2
=-5 ± √-75 /2.............(√-75=√25*3*-1=5√3 i as √-1=i)
x= -5+5√3 i /2 or x= -5-5√3 i /2
Denominator cannot be equal to zero.
Ans: zeros are 5, -5+5√3 i/2, -5-5√3 i /2
Meena from Strongsville,OH