Can you show me how to do this quadratic equation by factoring. w^2-2w=15. Step by step please, and how I can recheck the answer step by step. Thank you

w

^{2}- 2w = 15Make the equation equal to zero. It becomes

w

^{2}- 2w - 15 =0Now we'll expand the equation to get the factors...

- what numbers can be multiplied to give -15 and when subtracted from each other would give -2??

- that would be +3 and -5.

so we'll have the equation rewritten as;

w

^{2}+ 3w - 5w - 15 = 0(w

^{2}+ 3w) - (5w - 15) = 0w(w + 3) - 5(w + 3) = 0

(w - 5)(w + 3) = 0

(w - 5) = 0 or (w + 3) = 0

(w - 5) = 0

w - 5 = 0

w = 5

or

(w + 3) = 0

w + 3 = 0

w = -3

RECHECK:

substitute the values of w (5 & -3) in the original equation.

w

^{2}- 2w = 15(5)

^{2}- 2(5) = 1525 - 10 = 15

15 = 15 .......................so that's correct

now we'd use -3

w

^{2}- 2w = 15(-3)

^{2}- 2(-3) = 159 + 6 = 15

15 = 15 ..................That's correct too....YAY!!