Lowell C. answered • 03/04/14
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There is a vertical asymptote at x=2, a horizontal asymptote at y=0, and a removable discontinuity at x=1.
Philip P.
Yes, there is a discontinuity at x=2, but it isn't removable. The two x-1 terms cancel (and are thus removed). You can remove one of the x-2 terms in the denominator but not the other, so the discontinuity remains.
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03/04/14
Lowell C.
John,
As Philip noted, a discontinuity in a function is only removable if the term in the function that caused the discontinuity can be canceled. Another way to look at it is that a vertical asymptote, such as the one at x=2 in this case, is a discontinuity
that cannot be removed.
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03/04/14
John L.
03/04/14