write a function in the form y = mx + b for the line that contains the points (–6.4, –2.6) and (5.2, 9)

Question

 I am not good at this

Answer 1

First solve for the slope, m using the two points given. It doesn't matter which point you choose as point 1 or 2 as long as you're consistent.

 

m = (y₂ - y₁)/(x₂ - x₁)

 

point 1: (–6.4, –2.6)

 

point 2:  (5.2, 9)

 

m = (9 - -2.6)/(5.2 - -6.4)

m = (9 + 2.6)/(5.2 + 6.4)

m = 11.6/11.6

m = 1

 

put the newly found slope into the linear equation for m

 

y = (1)x + b

y = x + b

 

Now solve for the y-intercept, b

by putting one of the given points

 

9 = 5.2 + b

 

b = 9 - 5.2

b = 3.8

 

final equation:

 

y = x + 3.8