Dr Gulshan S. answered 02/19/17
Tutor
4.9
(52)
Physics Teaching is my EXPERTISE with assured improvement
Case 1
Open pipe ( open at both ends)
For fundamental Length of pipe = 2x Wave length /4= wave length /2
So wave length = 2x Length of pipe = 2*32 = 64 cm = 0.64 m
Speed = Frequency* wave length
Frequency= 350/0.64
= 546.875 Hz or 546 (+/- ) 2 Hz
Case 2 ( closed pipe ) which is closed at one end and open at other
Length of Pipe = Wave length / 4
Wave length = 4 *0.32 = 1.28 m
frequency = 350/1.28 = 273.43 Hz or 273 (+/- ) 2 Hz