Finding the roots of the function in exact form

Question

Find the roots of the function in exact form

 

f(x)=11 (^2x^2-5x+1) -1 Because I am posting via my phone I cannot express the precise equation. After f(x)=11 all the following numbers are exponents. I sectioned them off using ( ) Not sure if that makes sense

Answer 1

11^{2x^2-5x+1} - 1 = 0

 

11^{2x^2-5x+1} = 1

 

11^{2x^2-5x+1} = 11⁰

 

So, 2x²-5x+1 = 0

 

 x = (5±√17)/4