
Doug C. answered 02/09/17
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Hi Kristen,
The converse of p->q is q->p. For this case: if M is between points A and B, then M is the midpoint of seg AB.
False as illustrated by: A-----M--------------B
The inverse is represented by not p -> not q. If M is not the midpoint of seg AB, then M is NOT between A and B.
False: A-------------------M----B
Contrapositive: not Q -> not P. If M is not between A and B, then M is not the midpoint of seg AB.
True: M----A-------B. If M is not between it for sure cannot be the midpoint.
The contrapositive of an implication/conditional is always logically equivalent to the original.