(Consider upward as + and downward as -. Then g= -9.8m/s2

Question

A ball is thrown upward from the edge of a cliff with at 6m/s. (A) How fast is it going .5s later and in what direction. (B) how fsst is it moving 2s later and in what direction? (Consider upward as + and downward as -. Then g= -9.8m/s2

Answer 1

Lets state what we are given;

 

initial velocity, U = +6 m/s; acceleration due to gravity = -9.8 m/s^2

 

(A) after 0,5 s, the velocity V = U + g*t 

 

V = 6 + (- 9.8)*0.5; = 6 - 4.9 = +1.1 m/s (upward)

 

(B) after 2 s the velocity V = U + g * t

 

V = 6 + (- 9.8) * 2 = 6 - 19.6 = - 13.6 m/s (downward)