Steve S. answered 02/24/14
Tutor
5
(3)
Tutoring in Precalculus, Trig, and Differential Calculus
f(x) = -9x^2 + 4x + 7 = 0
x = (-b ± √(b^2-4ac))/(2a)
x = (-(4) ± √((4)^2-4(-9)(7)))/(2(-9))
x = (4 ± 2√(4+9(7)))/(2(9))
x = (2 ± √(67))/9
check:
-9((2 ± √(67))/9)^2 + 4((2 ± √(67))/9) + 7 =? 0
-4/9 ± (-4)√(67)/9 - 67/9 + 8/9 ± 4√(67)/9 + 7 =? 0
-4/9 - 67/9 + 8/9 + 63/9 ± (-4)√(67)/9 ± 4√(67)/9 =? 0
-71/9 + 71/9 ± (-4)√(67)/9 ± 4√(67)/9 = 0 √