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5n-n^2 factoring?

How do you know whether to factor out a (-n)?
 
If i did:
   -n(n-5)
 
but if i did:
   n(-n+5)
 
which one is correct?
The answer of my book says -n(n-5)
 
Do I always have to make sure that the n is a positive?
 
 

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Steve S. | Tutoring in Precalculus, Trig, and Differential CalculusTutoring in Precalculus, Trig, and Diffe...
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Both have the same value so are technically correct.
 
But custom dictates that the factors are presented in a way that makes it easy to mentally calculate the zeros, so -n(n-5) is preferred because it's easier to see that the zeros are 0 and 5.