
Steve S. answered 02/20/14
Tutor
5
(3)
Tutoring in Precalculus, Trig, and Differential Calculus
graph solution set
x <= y^2
y >= x
x = y^2 is a horizontal parabola with vertex (0,0) opening to the right.
So x <= y^2 means all points on the parabola and to the left.
y = x is a line through the origin with slope 1.
y >= x are all points on and above the line.
The line and the parabola intersect when x = x^2,
or x(x-1) = 0, i.e., x = 0 or 1.
The part of the parabola that comes into play is just that part above y = x; that’s y = sqrt(x) on interval [0,1].
So the solution set will be all points on or above sqrt(x) on the interval [0,1] and on or above the line otherwise.
See GeoGebra sketch here:
http://www.wyzant.com/resources/files/262542/region_solution_set
x <= y^2
y >= x
x = y^2 is a horizontal parabola with vertex (0,0) opening to the right.
So x <= y^2 means all points on the parabola and to the left.
y = x is a line through the origin with slope 1.
y >= x are all points on and above the line.
The line and the parabola intersect when x = x^2,
or x(x-1) = 0, i.e., x = 0 or 1.
The part of the parabola that comes into play is just that part above y = x; that’s y = sqrt(x) on interval [0,1].
So the solution set will be all points on or above sqrt(x) on the interval [0,1] and on or above the line otherwise.
See GeoGebra sketch here:
http://www.wyzant.com/resources/files/262542/region_solution_set