
Parviz F. answered 02/20/14
Tutor
4.8
(4)
Mathematics professor at Community Colleges
I think your question is How to factor The quadratic:
X^ 2 + 7 X + 10 =0
always f(x) = ( X +a ) ( X+b ) = X^2 + ( a +b ) X + ab
Roots , the values of X that makes f( x) =0
( X+a ) = 0 X1 = -a ( X+ b) = 0 X2 = -b
X^2 + ( a + b) X + ab = X^2 + ( X1 + X2 ) X + X1X2
with a =1
always : X1 + X2 = - b
X1 . X 2 = c
X^2 + 7X + 10 =0
- (X1 + X2) = 7 X1 . X2 = 10 ( 2)
2, 5 are the answer for X1 x2
then :
X^2 + 7X + 10 = ( X +2 ) ( X +5 ) =0 X = -2 X = -5
If System of equation( 2 ) doesn't have integer solution, then we have to factor by completing
the square.
for a ≠ 1
i.e.
2 X^2 + 7X +5 = 0 then -( X 1 + X2 )= 7/2 X1 . X2 = ( 5 /2)
again answer X1 = -1 X2 =- 5/2
To factor we break 7 into 2 +5
2 X^2 + 2X + 5X + 5=0
Factoring by grouping :
2X ( X + 1 ) + 5 ( X +1 ) = 0
( X +1 ) ( 2X + 5) =0
X = -1 X = -5/2