Riley M.

asked • 01/23/17

Math of Games

Inexperienced with teleportation, when GB leaves a particular location on the map below she always seems to end up at random at one of the three other locations. If GB is currently at position A on the map and teleports three times, what is the probability that she will end up right back where she started?
     A
B   C   D
 

2 Answers By Expert Tutors

By:

Jason L. answered • 01/23/17

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Graduate Student Who Loves to Do Math

Riley M.

But each teleportation causes her to land at one of the 3 other spots. Does that still make it 1/4?
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01/23/17

Jason L.

Oh ok I misread the question.
 
Teleport 1: She cannot wind up at A since she started there.
(1/3 * D) + (1/3 * B) + (1/3 * C)
 
Teleport 2: Regardless of where she started this one, the odds of getting back to A are now 1/3.
(1/3 * A) * (2/3 * B,C,D)
 
Teleport 3: Now we have to take into account 2 possible scenarios: 1) if she was on A after teleport 2, and 2) if she wasn't on A after teleport 2.
 
If she was on A, then she can't come back to A for this teleport.
 
P(Ended tp2 on A) = 1/3
P(Ending tp3 on A | ended tp 2 on A) = 0 * 1/3 = 0
 
If she wasn't on A, then once again the odds are 1/3.
 
P(ended tp2 on B,C,D) = 2/3
P(ends tp3 on A | ended tp2 on B,C,D) = (1/3) * (2/3) = 2/9
 
So adding up both scenarios for the third teleport 0 + 2/9 = 2/9.
 
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01/23/17

Mark M.

Probability is not the same as odds.
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01/23/17

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