Steve S. answered 02/19/14
Tutor
5
(3)
Tutoring in Precalculus, Trig, and Differential Calculus
f(x) = 3x^3 + x^2 + x - 4
-1 | 3 1 1 -4
-3 2 -3
3 -2 3 | -7
f(x) =(x + 1)(3x^2 - 2x + 3) - 7
check:
(x + 1)(3x^2 - 2x + 3) - 7 =? 3x^3 + x^2 + x - 4
x(3x^2 - 2x + 3)
+1(3x^2 - 2x + 3) - 7 =? 3x^3 + x^2 + x - 4
3x^3 - 2x^2 + 3x
+ 3x^2 - 2x + 3 - 7 =? 3x^3 + x^2 + x - 4
3x^3 + x^2 + x - 4 = 3x^3 + x^2 + x - 4 √