Let x = # individual tickets sold at $2 each
let y = # of 3-ticket sales sold at $5 each
x + 3y = 300
2x+ 5y = 528
Use substitution or elimination to solve
Since x = 300-3y
2(300-3y) + 5y = 528
600-6y+5y=528
72 = y
x = 300-3(72) = 300-216 = 84
84 people bought single tickets
72 people bought 3 tickets
72(3) + 84 = 216+84 = 300 tickets sold